(2n*2)/2^-5=2^2

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Solution for (2n*2)/2^-5=2^2 equation: 



(2n*2)/2^-5=2^2

We move all terms to the left:

(2n*2)/2^-5-(2^2)=0

We add all the numbers together, and all the variables

(+2n*2)/2^-5-2^2=0

We add all the numbers together, and all the variables

(+2n*2)/2^-9=0

We multiply all the terms by the denominator


(+2n*2)-9*2^=0

We add all the numbers together, and all the variables

(+2n*2)=0

We get rid of parentheses

2n*2=0

Wy multiply elements

4n=0

n=0/4

n=0

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